So why this expression is wrong?
"Asr=Area of semirectangle, Asc=Area of semicircle.
Then: Xcm=[Asr*(R/2)-Asc*( R-(4/(3*pi))*R)]/(Asr-Asc);"
I've considered the different masses, taking lambda= Mass(sr)/Area(sr), and the same for the sc.
And the result still wrong. I've used the coordinate...
Okay so the dA= (R-√R^2-X^2)dx, I understand that. But why you take x=(R/2+√(R^2-X^2)/2)?
And I tried to solve your equation with Maxima but i didn't get the result.
Okey, so the center of mass for the semicircle should be R-(4/(3*pi))*R?
Asr=Area of semirectangle, Asc=Area of semicircle.
Then: Xcm=[Asr*(R/2)-Asc*( R-(4/(3*pi))*R)]/(Asr-Asc);
Xcm=0.223*R;(I've reviewed my calculations)
Thank you, but when I try doesn't match with the correct answer.
Xcmrectangle= R/2
Xcmcircle= (4/(3*pi))*R
Xcm=(R/2)-(4/(3*pi))*R=0.0755*R
Correct answer: Xcm=(2/3)*R*(4-pi)=0.055*R
Homework Statement
Find the position of the center of mass for a thin sheet and homogeneous, with sides R and 2R ,from which has been subtracted a half circle of radius R.
[Xcm=(2/3)*R*(4-pi)]Homework Equations
Rcm=(1/M)*∫rdm
The Attempt at a Solution
By symmetry we know Ycm=0.
For de...