Yes I have learned about them. I have learned about the elastic collision (m1v1+m2v2=m1v1'+m2v2') and also Interlastic (m1v1+m2v2=(m1+m2)v')
I have an equation x=1/2(vi+vf)t. But that seems too easy.
Well since I know that Momentum=mass x velocity, the mass stays the same but velocity goes down. Therefore, the momentum goes down. But I am not sure on how that all fits into the distance.
A 0.400 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The bead collides elastically with a larger 0.600 kg bead initially at rest. After the collision, the smaller bead moves to the left with a velocity of 0.70 cm/s. Find the distance the larger bead...