Recent content by shaa

I think Khan Academy is probably your best bet. Honestly, I struggled tremendously with algebra based courses, and barely passed pre-calculus. Just be sure that you're determined and motivated, the teacher (or professor) will notice your effort and be more than glad to help you. My pre-calc...

Hahahah. Of course. It's the inverse reaction and it double. Thus 1/k2. Thanks? :P

It states that the equilibrium constant for reaction 1 is = k. The equilibrium constant for reaction 2 is = 1/k2. The answer makes complete sense given a general form of an equilibrium reaction, but why wouldn't the first reaction be = 1/k or the second be = -1/k2?

Are you referring to the mixing up of similar colours like red and orange? I can't tell the difference between the two, and it's quite irritating. XD

I'm actually curious how some people go about studying as well. Maybe not the "Greats" but people that can maintain a 3.8 or so in college. For instance, if a class was strictly homework and quizzes, I would have a 4.0, but tests really bring me down. I some how manage to NEVER score above a B...

I've heard that inside some of the gas planets in our solar system, the pressure is so incredibly high that Hydrogen assumes an unheard of state. That state being "Metallic" Hydrogen, so to answer the question, it is indeed possible. However it requires the pressure of Jupiter. XD

I've gotten the first question, considering that the second reaction is half of the first. Resulting in: x1/2, and x being the original Kc. I know what the answer to the first question is, but I'm having difficulty understanding why it is what it is.

Hello, I'm new to the forums and did in fact search for my thread before posting. I couldn't find anything that helped me with what I'm looking for. With that said, the problem I'm having is: 1) The value of Keq for the equilibrium H2+I2 → 2 HI is 794 at 25°C. What is the value of Keq for the...