Recent content by shabi
-
S
Trigonometric Applications - complex numbers
thanks figured it out both ways. i did it with the complex numbers as this is what we are focusing on at the moment. i was just forgetting basic integration rules. integral: cos.5x.dx let, u=5x du=5.dx dx=1/5.du so, integral: cos.5x.dx = integral: cos.u.1/5.du =1/5.integral: cos.u.du...- shabi
- Post #6
- Forum: Calculus and Beyond Homework Help
-
S
Trigonometric Applications - complex numbers
thanks for your help! but i still don't get it. can anyone explain step by step?- shabi
- Post #4
- Forum: Calculus and Beyond Homework Help
-
S
Trigonometric Applications - complex numbers
any help with me understanding this problem would be very much appreciated. Homework Statement show, ^{π/2}_{0}\int cos^{5}xdx = 8/15 hence show ^{π/2}_{0}\int sin^{5}xdx = ^{π/2}_{0}\int cos^{5}xdx where, cos^{5}θ = \frac{cos5θ + 5cos3θ + 10cosθ}{16} sin^{5}θ = \frac{sin5θ -...- shabi
- Thread
- Applications Complex Complex numbers Numbers Trigonometric
- Replies: 6
- Forum: Calculus and Beyond Homework Help
-
S
Complex Numbers - Complex Roots of Unity
Thanks for the prompt reply and pointing that out! So simple now i can see that.- shabi
- Post #3
- Forum: Calculus and Beyond Homework Help
-
S
Complex Numbers - Complex Roots of Unity
Need help with this please: Homework Statement (1 + cosθ + isinθ) / (1 - cosθ - isinθ) = icotθ/2 The first step in the solutions shows: (2cos^2θ/2 + i2sinθ/2cosθ/2) / (2sin^2θ/2 - i2sinθ/2cosθ/2) Homework Equations I can't get there. The Attempt at a Solution I tried multiplying by: (1 -...- shabi
- Thread
- Complex Complex numbers Numbers Roots Unity
- Replies: 3
- Forum: Calculus and Beyond Homework Help