Recent content by shannons

Thats an easier way of thinking of it :), thank you. How do I get the correct impulse? In the answer key, it says that the answer for b. is -9 N/s edit: I think the answer key might be wrong:( thank you for your help, I'm starting to understand this now :D.

2. What force must be imparted to a 100g baseball to change the velocity from 40.0 m/s to -50.0 m/s in 1.2 ms? b) What is the impulse of this force? delta p= pf-pi delta p= m(vf)-m(vi) delta p= 100(-50)-100(40) delta p= -5000 -4000 = -9000 is that how I set that up? If i...

Would I use the same formula for the next problem too?

I see, I did it in the wrong order. Thank you so much! :smile:

I thought I was supposed to calculate the momentum and put that in... -31.5= 6.3(Vf) - 6.3(6) -31.5/6.3= Vf - 37.8 -42.8= Vf Is that better?

When I tried that I got: delta p = pf-pi (change in momentum= momentum final - momentum initial) deltap=m(vf)-m(vi) 37.8=6.3(vf)-6.3(6) The answer for number 1 is supposed to be 1.0 m/s. Where am I going wrong?

Hello, Due to a teacher strike where I live, I've been trying to teach myself the momentum unit . Could anyone go through these questions with me? Or tell me what formulas I should use to solve these problems? 1. A mass of 6.3 kg traveling at 6m/s is acted on by a force giving an impulse...