Homework Statement
If a solution of a weak acid contains more HA than A-, then
Homework Equations
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The Attempt at a Solution
the answer is pH > pKa.
Okay my question is why is this the answer. I'm trying to understand in what situation you would have the pH greater or less...
First, I made a mistake in my last reply. I'm working on two of these problems with different numbers, but same setup. So I meant to say 6.0 not 5.91. Your explanation makes sense, that the horizontal velocity calculation in b. wouldn't need acceleration. I'm not sure how I ended up with the...
Thanks I got it now. I think I messed up on my drawing of the problem so I redid it and saw what I needed to solve for. Then b.'s velocity was just equal to the square root of 5.91^(2) + (acceleration*T)^(2). Then c. would just be the vertical velocity which was used to solve for b.
That's what I was initially thinking in the first post, you just have to take into account that gravity(acceleration) would be -9.8 m/s^(2). But I went onto another path for some reason. Now for the distance in a. I get 7.67 m. For part b. we know that the rocks are stationary and see the gull...
thanks for the help. This is weird because you are right that it can't be 0.8 seconds, however I was still able to use that as an input to calculate the right answer for a.(it is 4.6 m). I went back and tried to organize everything so I know what to do. As you said, y0 = zero because the clam...
alright, so for part a. this is what I did. First I took the formula y = yo + Voy + .5at^(2). yo is zero. The Voy is 8.00 m. Acceleration is -9.8 m/s^(2) and time is what I solved for. Time equals 0.816 seconds. Then I took the time and multiplied it by 6.00 m/s to get 4.89 m which is the...
Homework Statement
A gull is flying horizontally 8.00 m above the ground at 6.00 m/s. The bird is carrying a clam in its beak and plans to crack the clamshell by dropping it on some rocks below. Ignoring air resistance, a. what is the horizontal distance to the rocks at the moment that the...