Recent content by sheebajenny

I truly understand now, thank you very much for your help I had trouble with this one since the day before Thanksgiving. I really appreciate the help. Sadie

Yes I'm using 10m/s*s for gravity

correction then I first found acceleration and then I used that to find normal force and then force of friction for the second problem one so I got normal force=325N and force of friction as 70.4N

I did draw free body diagrams. For the second problem my only force I have is weight it seems like I must be missing something.

I may have figured it our #1 normal force sin37=320/N N=531.7 acceleration .5=10sin37-a/10cos37 a=2m/s*s with major rounding #2 normal force= 800N? force of friction=160N? accleration .2=10sin37-a/10cos37 a=-4.4m/s*s

here is what I know force of friction=coefficient of friction*Normal force. To find normal force you use SOH CAH TOA depending. They act opposing the force of in the first problem 800N. g*sin(theda)-acceleration/g*cos(theda) acceleration= 2*distance/time squared. I'm really having a difficult...

I've got 2 problems: Number 1: Greg is pushing a 32 kg crate across the floor. He is making like difficult by applying his 800 N force down at an angle of 37 degrees below the horizontal. The coefficient of kinetic friction between the crate and the floor is .50. I need to find the normal...