Recent content by Shenlong08

So I'm getting 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 Sorry for this double post, I clicked edit and didn't realize where I was typing.

A, B, C, and D are matrices, so I get multiple equations in which I'm solving by row reducing the matrix.

So I should expect my answer to be 3 out of the 4 vectors, or perhaps 2 then? That would make sense. I also need help with comparing vectors as matrices. With vectors in R space I know what to do, but for matrices I'm not quite sure. Suppose I have matrices A, B, C, D such that...

Homework Statement Suppose we have, Let V=span(v1, v2, v3, v4). Find a basis for V. (there are actual vectors given, however I can't exactly write them in an easy to read form) Homework Equations N/A The Attempt at a Solution My initial thought is, if I require a basis in...

I'm having trouble with a proof : u+v=v+u using the definition of a vector space (excluding the commutitive axiom of course), thus I have the other 9 axioms to work with. I'm not even sure if I'm using one of the axioms right; since I cannot say that u+v=v+u, I don't think that I should say...

I merely wanted to know which test I was using wrong, if you care to explain why the p series test does not apply, it'd be appreciated. jostpuur gave a reason, which if you verified, would be great.

The derivative was taken from the line (1/n)ln(n). 1/n was evaluated as 0. 1/n / 1/[ n*n^(1/n) ] (sorry i don't know how to make it more clear)

I'm not comparing the sequence by the above/below method, I'm saying if I compare it to the harmonic series through a ratio, then lim n-> infinity [ n*n^(1/n) ] / n lim n-> infinity n^(1/n) lim n-> infinity (1/n) ln(n) lim n-> infinity 1/n ...l'hospital's' = 0 -> e^0=1 and...

For lim n->infinity n^-(1+1/n), the p series test shows that it converges since (1+1/n) will be greater than 1, while doing a limit comparison test with 1/n gives 1 showing that it diverges since 1/n diverges. For which one is my thinking wrong about?