Yeah true not a solution. But this can be extended to the solution. Want to know if the assumption i made and the thought process is right? If so can extend the solution.
Okie. My equation never says height is measured in the square root of joules. But I have told amplitude is proportional to square root of joules. Hope this is clear. If you have to say anything on solution kindly comment. Will be happy to learn.
Also I have mentioned, I have not arrived at...
Find the solution here.
This can give the amplitude of the wave when steel ball just touches the water surface. One last step is remaining in this. Just check if it can be good to go.
I am not desperate. I am explaining why it is not m+v and mv.
1. I have mentioned in the bracket condition Conditions of friction, direction of force in both the cases are same.
2.More or less is happening because of the relation with the factor mass and velocity.
3. I am not confusing momentum...
KE is the effect by product of m and v.
If a force is applied for a body with mass 1 kg in such a way that it gets an initial velocity of v m / s. Now if the same force is applied to a body mass with 5 kg then what would happen to the initial velocity. Will it be v m/s or more than that or less...
If a force is applied for a body with mass 1 kg in such a way that it gets an initial velocity of v m / s. Now if the same force is applied to a body mass with 5 kg then what would happen to the initial velocity. Will it be v m/s or more than that or less than that. The initial velocity achieved...
Option is E.
Here when an object moves from point p1 to p2 in same time say x seconds and zero acceleration. To cover from p1 to p2 point, with minimum velocity in x seconds should have a shortest path. This should be a straight line. Hence E.
Okie. Energy Spent = Final Energy - Initial Energy. So in this ideal case the energy spent will be zero as there is no change in mass and velocity over period of time. So energy spent in case 1 and energy spent in case 2 = 0 and equal.
I give an initial velocity U to a ball on smooth surface and it covers say 1 m in t secs. Now for the same ball i give initial velocity of 2U. Under the same conditions as above thought it covers 1 m in half the time, to cover 1m the energy spent in both cases is same. Though ball in second case...
When standing also there will be internal work done in the body. External work will be zero as there is not displacement but within body work happens. Okie in my query it was external work i had to mention?
Okie, In the case of ball on frictionless surface. Consider that ball A takes 2 minutes to cover distance 1 m and ball B takes 5 minutes to cover distance 1 m. In this though time is different for the balls to reach the destination, but what would be energy consumed or energy required for ball A...
For a fixed non zero momentum = Does this mean the mass and velocity of the object remains same throughout or mass and velocity vary such a way that their momentum remains constant?