Hmm, its getting late atm, I will work on this tomorrow and get back
Thanks for the help
Also, just for reference, is there a better method for this integral, this substitution method seems to be pretty long.. Or is this the only method?
sHubH
Okay I'm getting
\int \frac {3 z^3 \, dz}{1 + z^6}
Using z=3\sqrtcot(x)
But, how do I proceed after that? Factorize the denominator and use partial fractions? or is there some part I am missing?
First, thanks for your fast reply
I substituted cot^3(x) as z
getting \int z dx
Now dz/dx = -3 cot^2 (x) cosec^2 (x)
so, dx = dz/[-3 cot^2 (x) cosec^2 (x)]
I replaced that in the integral
I have no idea how to proceed...
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While solving some integrals, I got stuck upon this one, and even after a lot of attempt, my friends and I could not solve it. Hence I...