Recent content by shubhangam

Hmm, its getting late atm, I will work on this tomorrow and get back Thanks for the help Also, just for reference, is there a better method for this integral, this substitution method seems to be pretty long.. Or is this the only method? sHubH

So.. any faster method?

Okay I'm getting \int \frac {3 z^3 \, dz}{1 + z^6} Using z=3\sqrtcot(x) But, how do I proceed after that? Factorize the denominator and use partial fractions? or is there some part I am missing?

First, thanks for your fast reply I substituted cot^3(x) as z getting \int z dx Now dz/dx = -3 cot^2 (x) cosec^2 (x) so, dx = dz/[-3 cot^2 (x) cosec^2 (x)] I replaced that in the integral I have no idea how to proceed...

Hi, I just registered on to the forums, and I have to say it is a very good job. I am currently a senior at High School and aiming for an Engineering Course. While solving some integrals, I got stuck upon this one, and even after a lot of attempt, my friends and I could not solve it. Hence I...