OK, confirmed: The the last number (1.195) shall be displayed as 1.20, otherwise a meticulous scientist looses information... :)
num2str([1.105, 1.115, 1.125, 1.135, 1.145, 1.155, 1.165, 1.175, 1.185, 1.195],3)
ans =
1.11 1.12 1.13 1.14 1.15 1.16 1.17...