Recent content by Siann122

Any replies I'm making from here on in are me blundering in the dark. This logic thing I'm really struggling with because I seem to not have any :P. As for CAF123's response, because the matrix is now (1x1 1x1) = (1 1). I don't get how that relates at all because the only way that that...

Then I'm honestly stuck given that I'm not exactly sure what you're asking, as I've never done induction with matrices before and my book doesn't explain how to do it with matrices specifically. I know that's a piss poor excuse but wrapping my head around it as a matrix as opposed to say a set...

That's my primary issue. Normally if there was An+1 I'd assume that A * An = B(n). I don't really know where else to go with that, I simplified both matrices down.

So An+1 = B(n+1). (Or at least to do induction I would assume this to be true). Still have kind of lost me though, how do I apply this to the question?

Homework Statement (1 1)^n = (1 n) (0 1) (0 1) Prove this through mathematical induction. Homework EquationsThe Attempt at a Solution I've replaced n with 1, so I've done that far. Then I said k = n. Then replaced all n with (k+1). I'm really stuck...

I was under the inference that because it's a homework question they're looking for it to be done in a certain way. If I can hand it in as a truth table then that would be swell.

That's correct, but I didn't use rules of inference, I drew up a truth table.

1. p ⇒ p ∨ q addition 2. p ∧ q ⇒ p simplification 3. p ∧ (p → q) ⇒ q modus ponens 4. ¬q ∧ (p → q) ⇒ ¬p modus tollens 5. (p ∨ q) ∧ ¬p ⇒ q disjunctive syllogism 6. (p → q) ∧ (q → r) ⇒ p → r hypothetical syllogism These are the rules that my lecture notes have written. I didn't write them because I...

Homework Statement Use the rules of inference to prove the following: (¬p ^ q) ^ (r → p) ^ (¬r → s) ^ (s → t) ) ⇔ t. Homework Equations Rules of Inference I guess. The Attempt at a Solution Honestly I don't know where to start using the rules of inference. I drew a truth table and...

Thanks very much, this works like a charm.

Thanks for sticking with me, I screwed up a few times with some silly errors :P. (2A + BT)-1 = 1/4 ½ 1 -1 (2A + BT)-1A = ¾ 1 -1 -1 Which is correct! Thanks!

Thanks so much for your help guys.

When I use that I get an error saying Matrix Dimensions Must Agree?

Yeah I picked this one up. Updated: 2A+BT = 4 2 4 1 Det (2A+BT) = 4 – 8 = -4 (2A + BT)-1 = 5/4 2 -1 -1 (2A + BT)-1A = (-1/2)(1)+(1)(2) (-1/2)(2)+(1)(3) (2)(1)+(-2)(2) (2)(2)+(-2)(3) =(21/4) (17/2) (-3) (-5)Det(A-1 * BT + 2I) = -12 - -16 = 4 (A-1 * BT + 2I)-1 =...

Alright, so by my logic a unit square is created through the following matrix: 1 0 0 1 And if I turn that above formula into a matrix, I will get the following: {2 6} {x} {1 3} {y} Is my logic sound? Does that matrix represent it or am I not quite getting it still?