Recent content by SilentBlade91

Ohhhh that is far simpler! Okay so I solved for I3 and had gotten 3.43A so I3+I1 would just be 3.43A+3.16A= 6.59A do you think this is correct? It makes sense to me because of the junction rule correct? Thank you for all your help btw!

Okay so solving for V1 i get 3.16A(4.20+8.12)=38.9312V Then I use that and do what I said on the bottom horizontal line, set E2+I4R4=38.9312V and set it so E2=38.9312V-I4R4 and replace that into my bottom loop equation so.. -I3R3-18V-I4R4+38.9312V-I4R4=0 Then I solve for I4 and I get 0...

yes but the positive and negative are switched on e2

Homework Statement For the circuit shown in the figure below, calculate the current I4 through the 2.18 resistor. As shown, R1 = 4.20 R2 = 8.12 R3 = 6.10 R4 = 2.18 I1 = 3.16A and E1 = 18V I couldn't get the picture on here but I will describe it: It is a parallel circuit, with...

Homework Statement Location A is 3.04m to the right of a point charge q. Location B lies on the same line and is 3.87m to the right of the charge. The potential difference between the two locations is VB - VA = 45.0V . What is the magnitude and sign of the charge? Homework Equations...

Ummmm, I was very confused by that explanation. I am unsure what you are trying to do. And why is the distance between speakers 2d and why is that relevant? It didn't seem to be used anywhere. It seemed like pythagorean theorem was used in your explanation but something was subtracted for some...

Here it is it is inverted for some reason but still...

The diagram is below..

this is all the information the problem gives

Homework Statement The two speakers are producing identical sound waves. The solid lines represent constructive interference regions and the dashed lines represent destructive interference regions. The point labeled 4 is 1228.5 m from the bottom speaker and 1618.5 m from the top speaker...

Homework Statement A boxcar of length 7.8 m and height 2.3 m is at rest on frictionless rails. Inside the boxcar (whose mass when empty is 2900 kg) a tank containing 1400 kg of water is located at the left end. The tank is 1 m long and 2.3 m tall. At some point the walls of the tank...

That F value I had was after I had already subtracted the frictional force

Turns out my answer was right.

Okay so I made separate free body diagrams of each. On m1 there would only be 2 forces correct? The FGm1-1764 going down and the T going up? Then on m2 there would be a Force of 299.442 (after subtracting the friction force) but then going that same direction as F would be T right? So I...

Okay well I tried doing something... I'm not sure if its right. assuming my force F is 107.028 then, T-F=m1a so T=m1a+F and m2g-T=m2a so replacing T as (m1a+F) i get... m2g-(m1a+F)=m2a that comes out to be a=(m2g-F)/(m1+m2) so I plugged in the numbers...