Yup! That's the problem, x is going to go to infinity, so I was trying to manipulate it 1/something to make it zero. If the exponent is x+1 over the fraction, it'll just go to infinity.
I'm trying to manipulate (x+1)^x+1 / ((x+1)+1)^x+1
So that I have a 1 in the numerator. If I bring the numerator down using the integer exponent rule, I'll have...
1 / ( (x+1) / (x+1) + 1 )^x+1 ?
Whoops, that's not right...
1 / (x+1)^x * ((x+1)+1)^x+1 ?