wow, thnx cristo, I've found the solution to question 1. Okay, i'll try to write down the formulas.
question 3
i assume we'll be using the formula Pt=mc\theta
so my solution,
P(20s) = 1.2 x 4200 x (40-25)
P(20) = 75600
P = 3780 W
is this right?
can anyone correct me if i am wrong.
question 1
0.5 x 360 = 160 x 0(teta)
0(teta) = 1.125 J
*why do we use 0.5
*is my answer correct? pls do tell me if I am wrong
question 2
12 x 0.32 x 9.8 = 0.32 x 128 x 0(teta)
37.632 = 40.96 x teta
teta = 0.91875 J
* is this correct...
Homework Statement
1. A bullet traveling at a speed of 360 m s-1 is stopped by a sandbag. Assuming half of the energy of the bullet becomes heat energy that is absorbed by the bullet, calculate the increase in temperature of the bullet. (Specific heat capacity of bullet = 160 J kg-1 C-1)...