Recent content by sinisterlink

nevermind i got it

A ski tow operates on a slope of angle 15.5 degrees of length 290m . The rope moves at a speed of 11.5km/hr and provides power for 50.0 riders at one time, with an average mass per rider of 75.0kg . Q: Estimate the power required to operate the tow. I missed class when he went over...

I think I got it. First I get the mass of the barbell by dividing 500 by 9.8 51.02 then i get the normal force the lifter uses. Fnormal = m(a+g) 51.02(.3175+9.8) Fnormal=516.195 + 93(9.8) = 1427.59 which is pretty close, if i didnt round i probbaly get 1430

A barbell is a pole that you do Bench Presses with. He's lifting it off the ground, I imagine.

is 1430 wrong ? is it actually the answer I got above? This is killing me, I have 9 more problems to go and I can't move on if I don't get this one right. I'm stubborn.

I have no clue how to get the acceleration of the barbell. Everytime I try my final answer doesn't come out to 1430N. i was using this formula: X(final) = X(start) + V(start)t + 1/2 at^2 .7 = 0 + 0(2.1) + 1/2a(2.1)^2 a= .3175 then F=ma 500(.3175)=158.73 + 93(9.8) = 1070.13 which...

How would I go about calculating the acceleration of the barbell? Do I have to take gravity into account if they give me .7m and 2.1s?

sorry, forgot to put in the units. My friend helped me out. But I'm completely lost. I don't know what to do first, this semester has been really tough on me. An athlete whose mass is 93.0kg is performing weight-lifting exercises. Starting from the rest position, he lifts, with constant...

An athlete whose mass is 93.0 is performing weight-lifting exercises. Starting from the rest position, he lifts, with constant acceleration, a barbell that weighs 500 . He lifts the barbell a distance of 0.700 in a time of 2.10 . Use Newton's laws to find the total force that his feet exert...