Recent content by six789

should i use the residual plot in comparing the industrailized countries vs. less-developed country? i mean, is it relevant if i use that? coz here is my thesis...What are the effects of population, GDP, GDP per capita and unemployment rate in the economy of industrialized country and...

do u know wat is prime factorization?

thanks vietdao again for helping me out...

anyone guys, is the third equation b^2 2n a^n-2 = 81,648?

is the thrid equation this... b^2 n a^n-2 = 81,648 anyways, why do u need to find the third equation, since you have the two?

guys, is it like this...? for t2 = nC1 (ax)^n-1 (by)^1 = 34992x^n-1y bna^n-1 = 34992 a^n = 6561 a^n = 3^8 therefore the answer for n = 8 and for a = 3, so you just have to find the b. but the second equation is bna^n-1 = 34992, so ill just substitute the values that i found... it is like...

guys, is it like this...? for t2 = nC1 (ax)^n-1 (by)^1 = 34992x^n-1y bna^n-1 = 34992 a^n = 6561 a^n = 3^8 therefore the answer for n = 8 and for a = 3, so you just have to find the b. but the second equation is bna^n-1 = 34992, so ill just substitute the values that i found... it is like...

anyone could help me with this question... in the expansion of (ax + by)^n, the coeffiients of the first 3 are 6561, 34992, and 81648., Find the value if a, b, and n. i did this... t1 = nC0 (ax)^n = 6561x^n a^n = 6561 t2 = nC1 (ax)^n-1 (by)^1 = 34992x^n-1y bna^n = 34992 but I'm not...

is it 1-(364/365)?

this is the problem... there are 25 students in a Data Management Class. Determine the probability that at keast two of them share the same birthday. (Assume that every year has 365 days) --> i have no clue what technique what to do here... coz this is a thinking question so its kinda hard for...

this is the problem... 1. nine horses are entered in a horse race. If you "box" three horses (three are chosen and they can finish in any of the first 3 positions in the race), determine the probability that you will hold the winning ticket. -->i tried this one... (3C1*3C2*3C3)/9C3 but my...

tide, ur so good! with ur explanation, i really understand it well...thanks man!

anyways, i found the solution for #2 but still i don't get the question in #1

and the most accurate way of timing the two events let's say a person observing and the person in the event (like in the rocket) is the cesium clock.

tide, i still cannot get the right answer. like i solve many times, but i really can't find the correct answer... i tried this one... 5C4*51*1/52C4, but its is wrong since the right answer in my book is 1/20825