Thank you both very much for your reply :-)
It's been a while since last time I went to school, guess old habits do die sometimes or at least needs refreshing. Another go then:
r = 2 /(2 - cos(theta))
r = 2 /(2 - cos(theta)) |* (2 - cos(theta)) both sides
r (2 -...
How to translate r = 2 /(2 - cos(theta)) to cartesian coordinates:
so far:
r = 2 /(2 - cos(theta))
r = 2 /(2 - cos(theta)) |* (2 - cos(theta)) both sides
r (2 - cos(theta))= 2
2*r - rcos(theta) = 2 | know x = rcos(theta)
2*r - x...