Recent content by slammedtgs

V at the point of the monkey is Sqrt(v0^2-2gh) So, (M+m)(v?) = M*Sqrt(v0^2-2gh) M*Sqrt(v0^2-2gh)/(M+m) will give (V?) So then take this new speed and use it in a new conservation of energy Equation? KE_i = KE_f + PE_f (.5)(Mtotal)(v?) + MGH = Etotal (0)+MHG = Etotal...

The velocity at pt. H would be Sqrt(2gh) so P=mv at H would give (M+m)*(sqrt(2*g*h) Kinetic Energy would be (.5)*(m+M)(2*g*h) So when H is max V is zero 0 +MGH = Etotal Etotal/MG= H? Is that another way of looking at it?

So this is what I was about to come up with, but I am not sure if it is correct. (.5)(m)(v*v) v= sqrt(2*g*h) so. (M+m)(sqrt2*g*h). (m+M)(m+M)/(2*g) =H? Am i on the right track here?

Well what i was thinking was that as he is rising he's slowing down, turning kinetic energy into potential energy. As soon as he grabs the monkey he is just added more gravitational potential energy to his system, thereby slowing him down. So if energy is not conserved we can look at the...

Homework Statement A circus acrobat of mass M leaps straight up with an initial velocity of vo from a trampoline. As he rises, he takes a trained monkey of mass m off a perch of height h above the trampoline. What is the maximum height attained by the pair in terms of M, m, Vo, h, and g...