Recent content by Slicktacker

Hi all, I have a question proving an identity: sin(4x) = 4sin(x)cos^3(x)-4sin^3(x)cos(x) I can't seem to figure it out. I know I should be using the known identities: sin(2x) = 2sin(x)cos(x) and probably: cos(2x) = 1-2sin^2(x) but I'm stuck. Please help! Thanks!

I tried the following: \sum_{i=3}^{4}(36+3i) and it worked. Weird...

Hi, I don't understand this problem at all: Rewrite the following sum with the index of summation starting at 3 in summation notation: \sum_{i=1}^{6}(5+3i) I know that the sum is 93 but I'm not sure what to do... Thanks for the help!

Does (\log_{x}a - \log_{x}b - \log_{x}c) = \log_{x}(\frac{a}{b/c})?

The denominator is (1+i)x-2

I get \frac{3}{2}x + 4 + \frac{23}{(2x-4)}, but where does the 1-i come in?

I did that, and now I have a 1-i in the dividend, so how do I divide by that term using polynomial long division (should I multiply it by 3x^2+2x+7 ?)

I tried the problem and I got 3x - 1 ... 3xi-i+6 ------ remainder -------- 1+ i ... (1+i)x-2 Anybody know where I'm going wrong?

I was learning polynomial division, and I can do most problems, except this one which is bothering me. : 3x^2 + 2x + 7 --------------- (1+i)x - 2 How would I divide something like that? Nothing is working. Thanks.