Recent content by slu1986

So the change in velocity is 0 m/s? How do you calculate the average acceleration during the turn?

final velocity = 9.12 m/s + 0 m/s

Could someone please help me understand how to work this problem?

Eastward component = 9.12 m/s Northward component = 0 m/s

I am sorry, but I am very confused now. final velocity = 9.12 m/s = 0 m/s.

Ok..so the initial velocity is the same as the final velocity 9.12 m/s?

Yes, I have studied vectors before in Biomechanics..I understand them, I just get confused by physics in general. So you're saying that initial velocity is 0 m/s. So the change in velocity would be 9.12 m/s?

I am so lost..I do not understand what you're saying. The only number I can come up with is 9.3 m / 1.60 s = 5.81 m/s. I don't know what other number it could possibly be?

would you use 9.12 m/s and plug that into the pythagorean theorum to get the initial velocity. 9.12 m/s^2 + 9.12 m/s^2 = 166.35 m/s and take sqr root = 12.9 m/s

So to find the initial velocity would you take 9.3 m^2 + 9.3 m^2 = 172.98 m and take the sqr rt = 13.2 m to get velocity = 13.2 m/1.60 s = 8.22 m/s <---initial velocity?

So would the change in velocity be = 9.12 m/s - 0 m/s = 9.12 m/s because the initial velocity is 0 m/s?

Would it be 58.4 m * 0.25 = 14.6 m speed = 14.6 m/1.60 s = 9.12 m/s

124 mi/2.01 hrs = 61.7 mi/hr 53.0 mi/0.83 hr =63.8 mi/hr So would I add 61.7 mi/hr^2 + 63.8 mi/hr^2 = 7877.33 mi/hr and take the square root of this to get = 88.7 mi/hr? I'm confused..could you explain to me exactly what vectors you are talking about when you say add the two vectors to...

I don't understand what vector value that I'm using the 30 degrees to solve for? Am I using it to get the resultant time or miles/hr? Do I take 53 mi/hr and divide that by .83 hrs and plug that answer in with the sin and cosine of 30.0 degrees to get the x and y components and then plug those...

C = 2 pi r = 2 * 3.14 * 9.3 m = 58.4 m 58.4 m - 0.25 = 58.15 m to get speed would it be = 58.15 m/ 1.60 s = 36.3 m/s