When I have worked out my own solution, I want to see if it is correct...the textbook I am using provides no solution. It is best to verify the plausibility of a solution if two people have done the problem independently. Even then, you can still learn even if both solutions are correct as the...
That first comment gabbagabbahey is really very unhelpful. What is one to do if they can't even begin to tackle a question? Surely that is is the best reason possible to ask for help! In future posts, would you prefer me to write down some wrong physics that I know is completely incorrect, just...
There are two "proper times" in this question...I was referring to the proper time of the Earth observer, trying to distinguish it from the proper time of the rocket observer.
I was approximating the outward journey into an "infinite" number of rest frames of the rocket. In each infinitesimal...
Here is an interesting question (units are Gaussian):
An infinitely long strgiht wire of negligible corss-sectional area is at rest and has a uniform lineare charge density q_0 in the inertial fram K'. The frame K' (and the wire) move with a velocity v parallel to the direction of the wire...
I don't think that is what I was doing.
For the accelerating observer, I was calulating the distance from the Earth by using an integral over the instantaneous rest frame differentials...
For the Earth observer I used his own personal time, not the proper time, in my calculations...
It...
It is the standard twin paradox. But these "paradoxes" aren't really paradoxes...and are usually down to some non-relativistic assumption that has been made - but perhaps hidden. It is rather like the "paradox" that a man can manage to fit a 10 foot ladder into a 5 foot long garage by traveling...
I see. I think what I meant is that each observer records the same distance between them at the time when he notices the other observer stops accelerating. But, I see this may not be true, since the two observers are not in a symmetrical setup. One cannot just suppose that the rocket is inertial...
Yes, I see. Although this only partially resolves my paradox. I am still wondering why my rocket observer looks back and measures a distance from the Earth that when divided by the time on his clock is greater than c...
Assume that a rocket ship leaves the Earth in the year 2100. One of a set of twins born in 2080 remains on the Earth (inertial frame); the other rides in the rocket. The rocket ship is so constructed that is has an acceleration g in its own rest frame (this makes the occupants feel at home). It...