Recent content by smartdesk

i meant 3m not 0.3 m

I assumed the length of he side of the square to be 0.3m, but it doesn't cancel out. So if the side were 3m, electric potential and work done would be: V=kq/r=(9.0*10^9)(0.2*10^-6)/3=600 N ΔU=q*V=(0.2*10^-6)(600)=1.2*10^-4 J

Homework Statement What is the work done in moving a 0.2 µC point charge from corner a to b of a square abcd, when a 10 µC charge exists at the center of the square? Homework Equations Work or ΔU=q*V V=kq/r The Attempt at a Solution V=kq/r V=(9.0x10^9)(0.2x10^-6)/r This is...