Recent content by sn3

Sorry about that - I meant expression. That gives me 3x^3y-2z^2(9x^6y^2+6x^3y^2+4z^4), which appears to be correct. So this equation works for when the numbers happen to have cube roots, but what if they don't (such as 28x^79y^5-18z^4). My calculator (TI89), which is absolutely great, can...

Hmm...I mentioned the cube root because I noticed it could make the equation simpler, but I honestly don't know what to do.

This is an incredibly stupid question, but how do you factor something like: 27x^9y^3-8z^6 I'm thinking somewhere along the lines of finding the cube root but that doesn't sound right. Any ideas on how to help me factor this? I don't need an answer, just how to do it. Sorry if this is...