Recent content by soccergal13

thanks again for all your help, i think i understand it now. i wasn't asking for a "100%" answer, i was asking for a hint to a solution that worked 100% for this problem, there is a difference. i'll watch my wording next time.

okay that i understand but that doesn't solve the problem of negative inifinty! lol. gah. sorry, I'm just getting really, really frustrated with this problem. and also if i needed the Cx+D on top... i do really appreciate your help :-), you have no idea!

solving for A, B & C I found, in order, 1/4, -1/4 & 1/2 (by multiplying each partial fraction by the whole quantity (x+1)^2(x-1)) and then making equations with the A, B, & C's.) ****The question remains of-- did I need to have Cx +D over the (x^2+1)^2 because since the bottom is a quadratic...

thank you all very much for your help :wink:, but does anyone know what a solution could be? what you're all suggesting makes sense, but nothing works 100%...

Thank you very much, that makes a lot more sense, but shouldn't it be Cx+D over the (x^2+1)^2? Also, when integrating each partial fraction from 0 to 1 (which is the second part of the problem), what do you do with the A/(1-x), because its going to be some number times the ln(1-x), which...

Evaluate the integral of x^2-x/(x^2-1)^2 from 0 to 1. * I know that I have to use partial fractions in order to make the integral integratable. My attempt at partial fractions: A/(x-1) + (B/(x+1)) + (Cx+D/(x^2-1)^2) Is this setup right? (Once I have it set up correctly, I know how...