Thereom was problem the wrong word, but this logic:
Since Bv=3v
Therefore (3I-B)v=0?
Say I subtract Bv from both sides
3v-Bv=0
(3-B)v=0
so why does (3-B)v=(3I-B)v
Are you sure? I checked it again. I'll show my a more exact version of my checks so it can be verified. But (3I-B) =
(1 -1 -1)
(-1 1 -1)
(0 0 2) -->
R2-->R2+R1
(1 -1 -1)
( 0 0 -2)
( 0 0 0) -->
R2-->-1/2R2
(1 -1 -1)
(0 0 1)
(0 0 0) -->
R1-->R1+R2
(1 -1 0)
(0 0 1)
(0 0 0)...
Alright - I'm coming into some difficulties. I understand the logic to find the solution. However, when I try diagnolizing B to get D, by using the eigenvalues I produce the same D(D=diag(1,1,3)). HOWEVER, I tried verifying this by finding the three linearly independent eigenvectors to form Q...
Homework Statement
I am having problems with (i)
Also I find my teacher to be very methodical, and lacking in theory. So if you find my reasoning poor or incomplete in any regard PLEASE enlighten me by clarifying. Thanks :D
12. (15 marks)
Let A =
(−1 −8 −2)
( 1 5 1)
( 0 0 1)...