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    Solving Particle Physics Relativity Problem: hbar*omega = DE (1 - DE/2Ea)

    Here's the problem: " A particle is in its first excited state with energy Ea, before it decays to its ground state with energy Eg by emitting a photon with an energy hbar*omega (omega = 2Pi*frequency) Why will the photon energy be smaller than DE= Ea - E? Show that: hbar*omega = DE...
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