Recent content by spacealgae

*Update* I figured it out!

Homework Statement Hello! I have a physics homework question I just need help at! What I am supposed to do is calculate the value for free-fall acceleration, ag, for each of my trials that I did in my lab. I supposed to use the equation for the period of the simple pendulum, T=2π√l/g, but I...

I believe that units of work are in Joules. And sorry, I know it's 'atm', not 'a t m', but that's just how my homework had it, so I thought I just would just keep it like that. An error in my homework grammar, I guess.

Ok, so 0.25 A t m = 25331.25 Pascal, which is 2.533125x10^4 in scientific notation. Would I then just multiply the two together? And no, I did all my calculations correct, the volume change is 1.7x10^-22m^3, I even had another person on here help me achieve that answer.

Awesome! Thank you very much! So now that's all figured out how would I multiply that by the atmospheric pressure, 0.25 A t m? Would I convert the A t m to scientific notation and then multiply?

Ok, so the final answer would be 1.7x10^-22m^3?

Homework Statement Hello, I just need help figuring out how to calculate the work done by the gas molecules for my physics homework :) Formula given: W=Px∆V (W=work, P=pressure, and V=volume) What I know: So my calculated volume is 1.7x10^-22m^3. Pressure=0.25 A t m (atmospheric pressure) I...

cubic meters?

Yes, yes, I realized I made a mistake and forgot to convert nm to meters. Physics isn't my strong suit, be patient with me. So, once I convert 1700nm to meters, that would be 1.7x10^-6. So I just need to multiply that to 1x10^-16m^2 to get 1.7x10^-22. I'm confused as to if I would add the m^2 at...

sorry, I just actually figured it out (I think) and got excited. But here we go from the top: How do I calculate the change in the volume produced by the piston? Given formula: ∆V=∆x∆d What I know: distance =1700nm Area of piston=1x10^-16m^2 What I think I figured out, through the help of this...

Wait my mistake, it would be 1.7x10^3*1x10^-16=1.7x10^-13

Which leads me to my final question, which is to take the volume I just calculated, and calculate the work done by the gas molecules, and the equation for that is: W=Px*∆V and I know that the volume is equal to 1.87x10^-13m^2, and the pressure is 0.25 A t m, so how would I multiply those two...

which would equal 1.87x10^-13m^2?

Ok, so I would just times 1.7x10^3*1x10^16m^2?

Ok, in scientific notion, that would be 1.7e-6?