Recent content by Sparky500

kinda understand. The reason i overlooked post#17 was due to me trying to hard to understand it myself. Thanks again. Sorry to be a pain but did you manage to have a look at that other thread for me? just in case you can reach it here https://www.physicsforums.com/showthread.php?t=174374 thanks

so this is the answer to the angular acceleration? (its by reading your posts that i am getting there) :P

i have had yet another go and would like to ask: is the angular acceleration 2.5136rad/sec^2?

thanks you have been a great help :)

hi, just noticed that i had a misprint in my original question above (sorry about this) in the question it says 30 secs whereas it should read 3.0 secs. therefore would my original answer be the correct one (sorry)

i have now worked out that angular velocity = 16rad/sec using \theta = {1/2} (\omega_{1} + omega_{2}) i calculated the distance to be 32rad please confirm.

sorry i have given the wrong answer for you to look at, the correct answer (one i have) should have read: =418.9 rad⁄s^2

Homework Statement A fan increases in speed from 500 to 700rev/sec in 30 seconds. What is the average angular acceleration during that time? Homework Equations The Attempt at a Solution The answer i get for this one is ∝=(700-500 rev⁄sec)/3sec any input appreciated

i am going to start this one over again using the information you have provided and repost what i get. Coul di ask you to have a look at this post for me https://www.physicsforums.com/showthread.php?t=174374 and let me have your thoughts? thanks

Unfortunately I have no book for this course. All I have is this paper and the formula. All I am thinking is since this is the formula that has been given to me, surely I must be able to resolve this question using that formula?

\theta = \omega t + {1/2} \alpha t^{2} In order to get the angular accelaration, I need to solve the equation with respect to \alpha , right?

\omega = \omega_{1} + \alpha t this is the formula given in class (if it can be read)

i can't relate this to me resolving theta?

\theta = \omega t + {1/2} \alpha t^{2}

1 rev = 2 pi rad