right, in my original post i did not step that far back into the linear form and i prob should have. Yes, i understand how that works.
And by using the alternate θ you solved the problem that i was having.
Thank you for your help and may you enjoy a wonderful motorcycle ride today. i...
well, to be honest, what little math background i have is failing me. i don't understand what you mean when you say "Have you attempted to analyze the setup mathematically?" i mistakenly thought that is what we were discussing.
Can you at give me a starting point? and maybe i can figure it...
ok, so going back to your original drawing/post it looks like i may have been using the wrong θ. If i use the θ between F & Ft the results come more in line. But i still don't understand how the eq. gets more complicated.
unless... you are talking about how the rubber band applies...
gneill, thanks for the reply.
from your reply i am guessing that you agrees with my co-worker that
F=2*s*ΔL*sin (θ)
where L' can be found using the law of cos. and the θ can be found using trig (S.A.S.)
i have found a couple of others that agree with this statement and understand...
yes i understand that. if you cut a spring in half it will take 2x the amount of force to stretch the same distance. that is a simple manipulation of Hooke. However it does not really help me in the situation described above.
and if it does, i don't understand how.
This is not a HW question, but a question that I need help solving. I am having an argument with a co-worker about the solution.
There is a 4ft sq sheet of plywood with an 18" wide rubber band stretched across it. To measure the spring constant (stiffness) of the rubber band a 6" diameter...