Recent content by Spruance

I believe that if you just put the numbers into a calculator, it gives you that (3*713 * 10^-9)/(0.120 * 10^-3) is 0.017825 Invers sinus of 0.017825 is the same as Sin(1.02)

sin theta = (n*lambda)/(d) = (3*713 * 10^-9)/(0.120 * 10^-3) = Sin(0.017825) = 1.02135136 tan (1.021) = (x/2.75) x = tan 1.021 * 2.75 = 0.049 0.049 * 2 = 0.098 m

Sin 0 = (n*lambda)/d = ((3 * 713 *10^-9)/(0.120 * 10^-3)) = 0.018 Sin 0.018 = 1.047 Sin 1.047 = (x/2.75) x = Sin 1.047 * 2.75 m x = 0.050 m

y = tan 1.02 * 2.75 m = 0.04896 m It cannot be correct

I really don't know what I have to do ...

I don't got any answer-book, but I am sure that my previous answer is wrong.

d sin 0 = n*lambda sin 0 = ((n*lambda)/d) = (3 * 713 * 10^-9 m/ 0.120 * 10^-3 m) = 0.017825 = Sin (1.02) tan 0 = y/r = y/2.75 m y = tan 1.02 * 2.75 m = 2.80 m

Red light with wavelength 713 nm pass through a double split with "split distance" 0.120 mm. The interference pattern gets observed on a screen that is 2.75 m from the double split. Find the distance between the two third order maxima we seeing on the screen. (My english is really awkward)

Ok. Let us assume that the initial speed is 4.43 m/s then the height of ball is given: h = 1/2 (3/4 vo2)/g + ho = 3/8 (vo2)/g + ho = 3/8 * ((4.43^2)/9.81) + 3 = 3.75 m Is that correct?

To solve for the initial speed v0: v0^2 = v^2 + 2gh - gh0 v0 = (v^2 + 2gh - gh0)^1/2 v0 = (2g(h-h0))^1/2 v0 = (2 * 9.81 (4 m -3 m))^1/2 v0 = 4.43 m/s What is wrong?

Ok. It is - 1 N, and not 1 N?

Of course. I am so extremely dull. Can you take a look at this? https://www.physicsforums.com/showthread.php?t=120003

Thanks What would then happen in d?

10.4 - 7 = 3.4 eV

I don't think the mercury atom would be ionized