Recent content by squexy

So I should not divide by 2 otherwise I will get x=0, I must be wrong from the begging how could I start to solve the 1 question?

I divided 5 by 2. x + 2y > 5 x + y > 5/2 x + y > 2,5

My apologies, the post was confusing. n= 5 x + 2y = n x + 2y > 5 x +y> 2,5 -x - y > -2,5 y > 2,5 - xx+2y > 5 x + 2(2,5 -x) > 5 x>0 x+y>2,5 y > 2,5

1 x + 2y > 5 x +y> 2,5 (.-1) x + 2y > 2,5 -x - y > -2,5 y > 2,5 x> 0 Log 9 - log 4´= log 5 5 * log 5 = 2^5 * 0,6989 2^3,4948 11,27300

-5px - p +2 = -5px +10 + 1 - p = 9 p = - 9

Sin^2 x -2(sinx . cosx) + cos^2(x)= a^2 -2(sinx . cosx) + 1= a^2 - 2(six . cosx) = a^2 - 1 7/9 = - a^2 + 1 7/ 9 -9/9 = a^2 2/9 = -a^2 a = √-2/9 -5px - p = -5px +10 + 1 - p = 11 p = - 11

´ Could anyone tell me if the resolutions of these questions are correct? Cosx = 4/3 - sin x Six - 4/3 - Sin x = 0 2 Sinx = 4/3 Sinx = 4/6 Cosx = 4/3 - 4/6 Cosx = 8/6 - 4/6 Cosx = 4/6 G(x) = 5x + 1 5*(px+2)+1 5px + p = 5px + 10+ 1 p = 11

If 2^x were smaller than 0 then -√2 would be accepted and √2 woudn´t?

My bad for posting wrong. Thank you all for the answers. Is this correct? 3u² - 3 = u² + 1 2u² = 4 u = √ 2 2^x = 2^1/2 x = 1/2

Could you help me with this questions as well? This is what I have done: 2^x - 2^-x/ 2^x +2^-x 2^x - 1/2^x/ 2^x +1/2^x u -1/u/u+1/u =1/3 3u² - 3/ 3u² +3= U u² - 1- u = 0 u² - u - 1 =0 (u -1) (u+1) =0 U =1 or -1

The answer is E. Since the line is passing the parable at x = 1 and 2 I used between these values to satisfy the inequality(x − 1)4< (x − 1)X = 1,5 (1,5 -1)4 < (1,5 -1) 0,0625 < 0,5 Is this correct?

37 By estimative I can find the answer, since radius is 5 coordinate units I decrease 5 from Y and add 5 to X having (7,-2) 39 a = b = c3x = 180 x = 60

Answer: K Answer: B Answer: C

Why is the answer "C" and not "B"?

Can someone show me how to resolve this question? The answer is G 1:3 Thanks ^.^