Recent content by sr-candy

Why not? the centroids of these triangles will form an arc

1. yes the arcs are of different radius, but you have the CM of the arcs, so you can consider the mass of the arcs are all lying on the y axis, all you have to do is calculate the CM of these "CMs" 2. laminar means layer or plane etc. Just think that a semi circle is formed with many sectors...

try considering rate of change of momentum

just consider the disk is formed with many semi circular arcs and for the converse case , there are 2 methods 1. consider the CM a semi circular shell, ie. a (disk) - (another disk with smaller radius), then take limit for the radius of the small one approach the bigger one 2. consider the...

nvm the problem is solved, what i don't know before is that if the solid can rest on any curve surface, the center of mass must lies on the contact surface of the cone and hermishpere thx for helping anyway

problem solved, thanks a lot

oh, sry my mistake "a" is given

i am trying , but one question if the "Newtons law" is wrong, then i can never solve sinA that means i hv 2 equations only, equation 1 and (s+a)^2=a^2+d^2 but i have 3 unknowns s, a, d is it possible to solve them?

i can't find any equation relating s , a , d except the geometry one

sure m2*g*d=2*m1*g*s s=(m2*d)/(2*m1)---------1 2*m1*g*sinA=m2*g sinA= m2/(2*m1)----------2 d/(a+s) = sinA------------3 d=a*sinA + s*sinA--------4 sub 1 and 2 into 4 d=a(m2/2m1)+(m2d/2m1)(m2/2m1) d= (m2a/2m1)+m2^2*d/4m1^2 (4m1^2d-m2^2d)/4m1^2=m2a/2m1 d=...

i am quite confuse here, 1.Isnt that your "conservation of PE" equation is exactly like mine? m2gd = 2m1gs 2*m1*g*s-m2*g*d=02.how can i know that it will rebound, and what is providing for the upward force?

thx for replying, i am very close to the answer, but i find that there is something wrong, i don't know if it is because of my calculation or my concept let the distance fallen of m2 be d and the distance raised of m1 be s by conservation of energy m2gd = 2m1gs---------1 by...

thx for replying :smile: let the height of the cone be h and the ground be my reference point Center of mass(CM) of the solid CM of the hermisphere * Volume of hemishphere + CM of the cone * Volume of the cone over the total Volume of the solid=...

Homework Statement A uniform solid consist of a hemisphere of radius r and a right circular cone of base radius r fixed together so that their planes are coincident. If the solid can rest in equilibrium with any point of the curved surface of the hemisphere in contact with a horizontal plane...

Homework Statement A light inelastic string passes round two small smooth pulleys A and B in the same horizontal line at a distance 2a apart, and carries masses m1 at each end and a mass m2(<2m1) at its middle point. The system is released from rest with m2 at the middle point of AB By...