Recent content by sricho

well I am just all confused now, is there any chance you could show me how its done , i would be very happy if you could. it will help loads with the other questions i have to do.

is this the equation i need ? Ac = - w^2 r Ac = - v^2 / r where w is omega how do i add this into the velocity equation?

sorry had a busy weekend so how do i use that acceleration in the equation i have. and what is the equation for the acceleration? thanks sam

Ncos θ - µNsin θ = mg N(cos θ - µsinθ) = mg N = mg / cos θ - µsinθ This is the equation i have for the normall reactiong force but you need the mass of the object where its not given. so I am stuck?

well i got my answer by using the equation for velocity and subsituting the values i have. so sqr(tan15 degree + 0.4 / 1 - 0.4 tan 15 degrees) x 60 x 9.8 but this doesn't use the normall reaction force and i don't think this answers the question

yes sorry that is the width of the car. so i need to work out the centre of mass. rite that makes sense with the given lenghs. was the equation for the velocity correct? pretty new to this so any help would be ausome thanks

Determine the maximum velocity at which a car can travel if the banking angle is 15º for the following conditions 1) It is not to slide radially outwards. 2) It is not to roll over. given: coefficient of friction as 0.4 r = 60m width of car is 2m and height from bank to centre of car is 0.5m...