Recent content by sromick

But I am solving for speed at b. That is velocity right?

I do not understand, so what do I have to solve for or what should I do?

I would solve for velocity here right? The height is 10 m. so v= sq root(2ke[at b]/m) so v= sq root(2(183750)/(750)) so velocity = 22.13594362 m/s?

One more question rockfreak, sorry about all this! What would be the speed of the car at the bottom of the first hill?

Thank you rock freak! My savior!

So 73500+183750=Pe+Ke Pe at C= m*g*h = 750*9.8*20=147000 so 73500+183750=14700(pe) + ke solve for ke = 242550 joules right?

So: PE for c = m*g*h =750*9.8*20= 14700 joules I use PEi+KEi=PEf+KEf right? PEi would be 14700 right? KEi would be what I calculated in B right? Whats PEf and Kef?

257250 joules + 0 joules = 73500 joules + KE (b) so.. 257250 joules = KE (b) + 73500 joules so.. KE (b) = 183750 joules correct?

Point B PE: m*g*h :750*9.8*10=73500 joules

Homework Statement 1. Assume the mass of the roller coaster is 750 kg. Answer the following. a) If the height of the first hill is 35 meters (measured from the ground), calculate the potential and kinetic energies at this highest position on the track. b) When the riders are at the first...