Recent content by Srumix

Homework Statement Find the conditional distribution function and density for the random variable X defined on R given that X is in some interval I = (a,b) where P(X in I) > 0. Assume that the density and distribution for the random variable X is known Homework Equations fX|X\inI =...

Hello, I'm not sure if this is the right forum, sorry if it's not! I have been called to an interview for a summer internship at a company as a "developer/programmer". I have never been to such an interview before and I would like to know if there's something special that I should do to be...

Thank you very much for your help Dick! :D

I'm not quite sure i follow the last line. Do you mean p(x) = (-x) on [-1,0], p(x) = x on [0,1]? EDIT: Never mind. I think i understand now. So if I write 2(1,0,0) + 3(0,1,0) + 4(0,0,1) that would mean the polynomial p(-1) =2, p(0) = 3, p(1)=4. So i have to find a linear polynomial that...

Hi Dick! Yeah I thought along those lines as well. But I could only come up with a basis sort of like {p(0),p(1),p(-1)} but i guess that's not really right. The basis would have to be 3 dimensional as well right? Otherwise I would have gone for {0,x} but I know that's probably not correct...

Hi Folks! Let A be the space of splines of degree one that have only one interior knot, at the point x = 0. Or in other words: A is the 3 dimensional space of linear polynomials on [-1,1] that consists for straight line segments joined at x = 0. How exactly do I visualize this space? The...

Eureka. Thank you so much! If I'll be back if i run into trouble but i think i should be able to handle it now :)

Im afraid I'm lost. How am I supposed to count the elements of the group generated by hk. Is there any general trick or hint that could be used here?

Alright. So if we assume that r > s we know that HK contains h^s for the integer s. We can then form a cyclic subgroup generated by h^s and we can conclude that r divides |HK|. Am i on the right track?

So if i assume that h gen H and k gen K. If i form the group HK generated by hk and form the subgroups of HK generated by h and k respectively theb their order must divide the order of HK since HK is cyclic. We then have by the fundamental theorem that the order of HK is rs since r and s are rel...

I will ponder this while I try to sleep tonight! Thank you so much for your help micromass, I sincerely appreciate it!

I'm using the book "A First Course in Abstract Algebra by John B. Fraleigh (7th ed). The problem is the last of section 6. Yeah, If I had known to check the order of the subgroup product (or that such a thing could be calculated in that way) I probably wouldn't have gotten stuck.

Alright fantastic! Thank you so much for your help. I do have a couple of questions: 1) (I realize that this may come up when i try to find a generator). I'm a bit worried that we haven't at all used the fact that G is abelian. Is it even necessary that G is abelian? 2) Are there any...

If g is in both H and K then the order of g must be a divisor of r and at the same time a divisor of s. But since gcd(r,s) = 1 then g must be of order 1 and is the identity element. Is this correct? :)

To be honest, I really don't know. The author has not introduced group products as of yet. But after looking it up i can see that |HK| = |H||K|/|H and K|. I know that finite cycling groups of order o are isomorphic to the congruence group mod o. So |HK| = r*s/(r-s), given that r>s. (this is...