Recent content by sruthis

Oh i forgot to factor in the perpendicular. Thank you!

well the torque equation uses sin and when you draw out a picture you will notice that sine works best for the Y component of the Force.

oh sorry about that. 1) Well I know that T=Fsin(angle)r and when I set it up T=(8.00kg x 9.8)(sin 30.0)(0.550m)=21.6 Nm That is the answer I originally had but according to the sheet I am working from the answer is 37.4 Nm...did I do something wrong in my calculations or in seting up the...

Please can someone help me with these two problems: A man is holding an 8.00 kg vacuum cleaner at arm's length, a distance of 0.550 m from his shoulder. What is the torque on the shoulder joint if the arm is held at 30.0 degrees below the horizontal? A 15.0 kg child sitting on a...

ohh. thank you so much. i completely did not realize that F/A was the stress. Thank you thank you.

I think I need to somehow use the equation F/A = Y(change in L/Linitial) and solve for Linitial, and i guess plug that value into the stress equation? but i do not know how to find A, and I am not sure if I have the right idea.

Please I need help with this question. I know I have to use the stress = elastic modulus x strain equation, but i do not know how to apply it to this particular problem. A Bone has a young's modulus of about 18 x 10^9 Pa. Under compression, it can withstand a stress of about 160 x 10^6 Pa...