Recent content by stargazer843

@Chronos Eventually it will be redshifted out of the electromagnetic spectrum though right?

Since light emitted farther away from our point in the universe is more and more red shifted, would this mean that at a certain time we wouldn't be able to observe light further than a fixed distance since it's been red shifted beyond the electromagnetic spectrum?

ah ok, now I understand. Thank you for all the help guys! :D

Once I get it to ∫1-du/u² If I separate it: [∫(1/u²)]-[∫(du/u²)] [∫(1/u²)du]-[∫(1/u²)du] This = 0 I can only separate it at the beginning?

first case, and ill remember that next time, although this isn't homework

∫1+sinx/(cosx)² dx I made u = cos x. du = -sinxdx -du = sinxdx so: ∫1+sinxdx/(cosx)² = ∫1-du/u² = ∫ (1/u²) * (1-du) This is where I got stuck. the 1-du is throwing me off. distributing would get me nowhere and I don't know how to get rid of the 1. Please help!

This rule also applies to exponents of X or Y right, not just e? so the derivative of x^(x²) would be 2x*(x²)*x^(x²-1)?

ohhhh. so derivative of e^2x would be 2*e^2x? and integral of e^2x would be (e^2x)/2?

so x is constant, but ln(2)*x is not? how do I differentiate between those two situations? would 6x+4x²+5y³ be constant or a function of x?

the integral and derivative of e^x is e^x itself. I was told that the derivative and integral of e to the ANYTHING power is e to that something power, meaning that: ∫(e^(6x+4x²+5y³))dx is e^(6x+4x²+5y³) and d/dx(e^(6x+4x²+5y³)) is e^(6x+4x²+5y³) However I recently saw an equation...