Recent content by StarlitVarsh

I found the solution by taking the total effective resistance of the 3 and 6-ohm resistors, and multiplying with the current of the entire circuit - and the solution I found was accurate to the answer key. Thanks for the suggestion, though!

I found the solution soon after my initial post, but thanks anyways!

I'm a student in high school. I used to dream of being an astrophysicist, but my passion for music production and songwriting became far greater, and that's my current ambition and dream. I still find physics sorta fun though, so here I am!

Honestly, I'm not sure. I learnt the concept just a couple hours ago, so I'm not sure how most of the questions in the topic work.

So far, here's what I have: Taking the parallel-connected resistors alone, 1/Total effective resistance (R) = 1/3ohm + 1/6ohm = 1/2, so R = 2ohm Replacing the 3 and 6 ohm resistors with a 2 ohm resistor, the total resistance will be 2+4 = 6ohm Using V=IR, I (current) = V(potential...