Recent content by stathike

I had to subtract X, so now I have to add X. (X+Y)+X = 2X+Y So, 2X+Y is the final answer. Edit: Thank you very much.

Since Ball A is not moving, it has 0 momentum. So, for momentum to be conserved, the speed of Ball B after the collision would be X+Y. Still, not sure how to "transform" that though.

So, if Ball A were not moving, then Ball B would be coming towards it at speed X+Y. Ball B would bounce back at speed X+Y. So X+Y is the final answer? What, if anything, do I have to do once I come back to the lab view?

Sorry if I seem a bit dense. 10+10=20 mph So would that mean X+Y?

The relative speed of B w.r.t. A is Y-X (or is it -Y-X?)

Doc Al: If I view it in a frame with Ball A at rest, then that means Ball B bounces back with speed X-Y (maybe absolute value of X-Y). Is this correct? Do I have to "tranform" it once I come back to the lab reference view? nrqed: I haven't ignored your post, I'm still working on getting this...

Doc Al: Thanks for the reply. I don't quite understand what you mean. Should I see the problem from Ball A's point of view, and then use relative speeds? How would I go from there? nrqed: Thanks for the reply, sorry for not being clear. The equations I listed in the "relevant equations" part...

Homework Statement Two balls, Ball A on the left, and Ball B on the right, are moving towards each other. Ball A is much bigger and heavier than Ball B. Ball A is moving with speed x, and Ball B is moving with speed y. They collide, and an elastic collision occurs, sending Ball B rebounding...