Recent content by Ste

I think I've just been looking at the equation in the wrong way because of the way the graph is labeled in the book. Let me explain how I now understand the equation and we'll see if I'm getting the hang of all this lol. S=1/2at^2...displacement equals half the acceleration, multiplied by the...

Hi sourabh. In the book it shows that at=5 (with at being the distance traveled along the y axis) 5 squared =25 Cheers.

Well, to be honest, that last bit was a bit over my head as I'm still learning how to rearrange equations. Why didn't I pay attention at school lol. The bit I still don't get is why I get the answer s=12.5, when common sense says the answer is s=10. Here's how I work through the equations...

It is constant acceleration because the book says it will go into non-constant acceleration later on. This is supposed to be the easy bit lol. Also, the line is straight. Like a right angled triangle.

Thanks for the reply salad. I've checked the book and the initial velocity does equal zero. Am I right in thinking that the two equations are interchangeable ? Maybe that's where I'm going wrong? I'll look into photo bucket when I get home. Thanks again.

Hi all, apologies if this is in the wrong section but I thought it would be ok as it's kind of homework related. I'm 35 years old and I'm trying to learn a bit about physics. With that in mind I thought I'd start at the G.C.S.E level seeing as I can't remember a thing from school. I borrowed...