so 1/2|VxW| would give the area, VxW=(A-B)x(C-B), could you foil and get AxC-AxB-BxC+BxB, and BxB=0, and -AxB=BxA, and -BxC=CxB. So I end up with 1/2|(AxC)+(BxA)+(CxB)| which is all backwards. @stevendaryl
Homework Statement
The three vectors A, B, and C point from the origin O to the three corners of a triangle. Show that the area of the triangle is given by 1/2|(BxC)+(CxA)+(AxB)|.
Homework EquationsThe Attempt at a Solution
I know that the magnitude of the cross product of any two vectors...