Recent content by stellies

Plain childish. I am studying IE and I am very good at mathematics. I just got my engineering week test results back and I will yet again pass Engineering maths with distinction. So grow up. Every engineer becomes an industrial engineer. Industrial Engineers just become IE's faster. No matter...

Hi I think I finally got it. The new rms must be 500 m/s . .. . . . ? Has to be.. If it is, it is actually simple and I actually feel silly that I was so blind. But thanks a lot for your help and sticking it out

Right, thanks I really didn't see that last part (4PV)... Anyway... Here is another shot at it: 250 = sqrt(3RT/M), therefore 250 = sqrt(3PV/m) 62500m = 3PV By doubling P AND V (4PV) 62500m 12PV and then 15625 = 3PV/m <=> 15625 = 3RT/M <=>...

Hi me again...I tried to work it out and I got an answer of 353.55 m/s...(if allowed) is there any chance that that may be right ?

Hi thanks for sticking out for me... So after sticking in RT = PV/n into v(rms) = sqrt(3RT/M) I get: v(rms) = sqrt(3PV/m). 250 = sqrt(3PV/m). Now somehow I need to get an expression where P and V is doubled..and I can't seem to get to that point :-( ... if 62500 = 3PV/m...

Hi thanks for the replies. But I still can't seem to get my head around this one. Could you please elaborate on the last statement: You have two equations: PV = nRT and V(rms) = sqrt(3RT/M). (and also the definition of n). Put those together to get one equation without T, and you'll...

Hi, I have a thermodynamics problem which I tried to solve but have no idea whether my attempt has been succesful. Here is the problem: Initially the translational root mean squared speed of an atom of a monatomic ideal gas is 250 m/s. The pressure and volume of the gas are each doubled...