Okay i understand the phase simplification,
Φ = arctan(1000/ω)
For amplitude the numerator magnitude is ω?
But I'm not quite sure how to get the magnitude of the denominator, can i go:
√(ω^2 + 1000^2)
Which would make the total amplitude ω/√(ω^2 + 1000^2)
Using complex conjugate I get:
(ω^2)/(ω^2+1000000) + (1000 j ω)/(ω^2+1000000)
This is at least separate in real and imaginary parts.
For the answer to this question my attempt is
A(ω) = √ (ω^2/(ω^2+1000000))^2 + ((1000 ω)/(ω^2+1000000))^2
Φ(ω) = arctan((1000 ω)/(ω^2+1000000) /...
Ok I understand some of this:
It is a high pass filter because at high frequencies the inductor acts as an open circuit
At ω = 0, T(ω) =0
At ω = ∞, T(ω) = 1
I can also figure out the break/cutoff frequency, which is asked in the following question, ωb = R/L = 1000 rad/s
The part I am still...
Homework Statement
Attached image has full question and information.
Determine the transfer function of the circuit. I've done this part, what I am struggling with is converting it into the form requested.
R = 10 KΩ
L = 10 H
Homework Equations
Voltage divider: Vo = R2/(R1 + R2) Vin
Impedance...