OK I talked to a friend of mine who says the answer is simply 20. The question was how many times would the client expect to try before connecting and since the probability of connection is 1/20 then he would expect to get connected 1 time if he makes 20 attempts.
Do others here think that...
I honestly don't know. I'm back to where I started. I don't know how to figure out how many times the user should expect to try before getting connected.
Homework Statement
A client is trying to connect to a web server on an overloaded machine that only accepts an average of one in 20 connections.
How many times would the client expect to try before getting a connection? Explain your answer.
The Attempt at a Solution
This is part 5 of...
Ohh I think i get it now. So zero state response would be like if you had an RLC circuit with no energy contained in the inductor or capacitor yet (because the circuit hasn't been used yet) but you start feeding the circuit some input signal. Zero input response would when you have energy...
assuming base 2:
log30=4x is equivalent to writing 2^4x=30
log30 is equivalent to writing (log30)/(log2)
This means (log30)/(log2)=4x
assuming base 8:
log12=5x+4 is equivalent to writing 8^(5x+4)=12
log12 is equivalent to writing (log12)/(log8)
This means (log12)/(log8)=5x+4
I...
Hmm ok so would that be like the amplifier outputting noise even when there is no inputs? Would that be the zero input response?
I still don't understand the state of the circuit and the zero state reponse.
I never heard about infinite impulse response. That's pretty interesting and I...
Hi, can someone explain to me, in simple terms, what zero input and zero state response mean? I know the terms should sort of be self explanatory in that zero input reponse is the response of a system when there's no input but how does that make sense?
This is how I'm imagining it in my head...
Oh, really sorry. The original poster wrote: "y values are defined at -1, 0, 1, but nothing in-between." I wasn't paying attention and just noticed the words "nothing in-between" and ignored the [-1,1] domain info. Yes you're right and I'll edit my first post. It is a finite discontinuity...
I think you misread what I typed :) . I wrote:
Question 2 has a finite discontinuity because you can count how many points are off the rest of the graph. Question 1 has inifinite discontinuity. Also the x=.01 and stuff was still referring to question 1. Sorry for the messiness. I should use...
What have you tried? Here's a quick summary of the steps...
step 1:
4x^2-1/2x(x+1)^2 = A/2x + B/(x+1) + C/(x+1)^2
step 2:
4x^2-1/(x+1)^2 = A and evaluate at x=0
Step 3:
*Solve for C before you solve for B:
4x^2-1/2x = A(x+1)^2/2x + B(x+1) + C and evaluate at x=-1
Step 4...
There are two types of discontinuities but I'll get to that later. A function is discontinuous if you can't draw the entire graph without picking your pencil off the paper. In question 2, you say there's a point just below the rest of the graph. Clearly you can't draw the entire graph unless...
The equation can be treated like a normal quadratic equation.
use substitution and replace "sinx" with "x"
2(sinx)^2-3sinx-2=0 ----> 2x^2-3x-2=0
factor the equation
2x^2-3x-2=0 = (2x+1)(x-2)
Replace "x" with "sinx"
(2x+1)(x-2)=0 -----> (2sinx+1)(sinx-2)=0
If you aren't...
F=ma where F=net force on the bullet=848N and m=mass of the bullet=.0018kg. Find a
Vf=Vi+a*t
Vf, Vi and a are all known at this point. Solve for time.
Your answer is close. You are off by a factor of 2.
Hints:
1. Draw a diagram showing the canoes and which way they are moving
2. Think in terms of vectors because you need to add velocities in this problem
3. Why are you adding velocities? Well one of the canoes is flowing downstream at 2.9m/s. This isn't just because the person in the canoe...