Recent content by stipan_relix

You were right, just got an email from the professor that he forgot to include the cable lengths. Thanks for trying to help!

So do you think this is unsolvable without cable lengths?

This is the first part of the problem, which I solved. Now to the second part which I can't manage to find the equations I need to use. Problem: This plant is connected to a 20/0.4 kV transformer of 250 kVA power, through an XP00-A cable (4x150 mm2, IN=300 A, Z1=0.26 Ω/km). a) Calculate...

Okay I think I kind of understand it now. Thank you.

Alright, but how does that fit into the maximum power transfer theorem if RT=R=10Ω then gives me IA=3 A and with that IA I get Vab=40V? Because the first time I solved for IA, I did it like R wasn't there at all, but since RT=R=10Ω, shouldn't I solve it using R in the equation as well?

It says 40V for me, not 60V? I also thought Vab = Vth?

I am confused now. Isn't the Vab I got also Vth? Where did you get 30 V from?

This gives me Vab = 20V, but my way above got Vab = 40V?

Maybe it's: IR3=I+I-IA ? With direction to the left?

So according to the "maximum power transfer theorem", R=RT=10Ω. Thank you. From that, the equation for IA should be: E1-IAR3+IR3-IAR-IR-IAR4=0 -20IA=-30-10-20 IA=3 A and for Uab: Uab=-IAR4+E1-IAR3+IR3=40 V Now I can get IR=ET/RT+R=2 A and PR=I2*R=22*10=40 W. Hopefully I did everything right...

Homework Statement In the circuit shown, in the image, the variable resistor R is consuming maximum power. Determine: a) resistance for R b) power for R c) current for R3 and its direction Homework EquationsThe Attempt at a Solution I tried getting IA(the direction is shown with arrows in...

Alright, if I wanted to get P for the current source, I'd have to first get the voltage for that current source, there's no way around that, right?

Sorry, the link showing my work was somehow private, I fixed it.

Hi. I am practising for my test and since I don't have the correct answers, I don't know if what I'm doing is right. I tried to solve this problem, can you check it and correct if it's wrong? Here's a clearer picture of the circuit. I suspect Uab isn't right, but am not sure. Thanks...

Thank you, I'll try it and report back!