How to find power and voltage using the mesh current method?

AI Thread Summary
To find power and voltage using the mesh current method, it's essential to first show your work before seeking help, as per forum rules. The user initially struggled with calculating Uab and sought validation for their approach. After correcting a link to their work, they received confirmation that their results were generally accurate. The discussion emphasizes the necessity of determining voltage across the current source to calculate power effectively. Overall, understanding the mesh current method is crucial for solving circuit problems accurately.
stipan_relix
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Member advised to use the formatting template for all homework help requests
Hi. I am practising for my test and since I don't have the correct answers, I don't know if what I'm doing is right.

I tried to solve this problem, can you check it and correct if it's wrong?
unUAKCg.png


Here's a clearer picture of the circuit.
aYSEOEy.png


I suspect Uab isn't right, but am not sure. Thanks!

EDIT: My work picture link was wrong, sorry.
 

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Thanks for posting in homework, but you deleted the template. Most important, you didn't show us your work. Our rules do not allow helpers to help until you show your attempt at solution first. In other words, we don't do the problem for you. We help you to solve it.
 
anorlunda said:
Thanks for posting in homework, but you deleted the template. Most important, you didn't show us your work. Our rules do not allow helpers to help until you show your attempt at solution first. In other words, we don't do the problem for you. We help you to solve it.
Sorry, the link showing my work was somehow private, I fixed it.
 
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Your results look good.
 
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Alright, if I wanted to get P for the current source, I'd have to first get the voltage for that current source, there's no way around that, right?
 
stipan_relix said:
Alright, if I wanted to get P for the current source, I'd have to first get the voltage for that current source, there's no way around that, right?
Well, no way that's any simpler.
 
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