How to find power and voltage using the mesh current method?

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SUMMARY

The discussion focuses on using the mesh current method to find power and voltage in electrical circuits. Participants emphasize the importance of showing work before seeking help, adhering to forum rules. The user expresses uncertainty about their voltage calculation (Uab) and seeks validation of their approach. The consensus is that calculating power (P) for a current source requires first determining the voltage across it.

PREREQUISITES
  • Understanding of mesh current analysis in circuit theory
  • Familiarity with electrical power calculations
  • Basic knowledge of voltage and current relationships in circuits
  • Ability to interpret and analyze circuit diagrams
NEXT STEPS
  • Study the mesh current method in detail, focusing on its application in complex circuits
  • Learn how to calculate power in electrical circuits using the formula P = VI
  • Explore common mistakes in voltage calculations and how to avoid them
  • Review circuit analysis techniques, including nodal analysis as a comparison to mesh current
USEFUL FOR

Students preparing for electrical engineering exams, educators teaching circuit analysis, and anyone looking to deepen their understanding of power and voltage calculations in electrical circuits.

stipan_relix
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Member advised to use the formatting template for all homework help requests
Hi. I am practising for my test and since I don't have the correct answers, I don't know if what I'm doing is right.

I tried to solve this problem, can you check it and correct if it's wrong?
unUAKCg.png


Here's a clearer picture of the circuit.
aYSEOEy.png


I suspect Uab isn't right, but am not sure. Thanks!

EDIT: My work picture link was wrong, sorry.
 

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Thanks for posting in homework, but you deleted the template. Most important, you didn't show us your work. Our rules do not allow helpers to help until you show your attempt at solution first. In other words, we don't do the problem for you. We help you to solve it.
 
anorlunda said:
Thanks for posting in homework, but you deleted the template. Most important, you didn't show us your work. Our rules do not allow helpers to help until you show your attempt at solution first. In other words, we don't do the problem for you. We help you to solve it.
Sorry, the link showing my work was somehow private, I fixed it.
 
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Your results look good.
 
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Alright, if I wanted to get P for the current source, I'd have to first get the voltage for that current source, there's no way around that, right?
 
stipan_relix said:
Alright, if I wanted to get P for the current source, I'd have to first get the voltage for that current source, there's no way around that, right?
Well, no way that's any simpler.
 
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