Recent content by Strand9202

I guess I am just lost on the last line, because I know the first 2 lines are true because of concave down.

Here is the problem (8b). I was asked to write out why the circled part was true. I know that since the function is concave down then f"(x)<0. That is a fact. What I am having trouble with is why they can say the next part. What I thought was L(x) is the tangent line and all tangent lines...

Sorry I thought I put the right side pictures up. I reedited and attached the correct ones.

My work for number 6 is correct. My teacher checked it, but they said I could have used a calculator to find it quicker.

Attached is the problem and my work through the problem. I got the problem correct, but my teacher said this could be done quicker on a calculator. Any idea how it could be done quicker.

I did that. I let f(x)=sin. That way my overall function reads square root (sin(x^2)). I got that my final answer was 1/2(sin(x^2))^(-1/2) * -cos(x^2)*2x. Which does fit with my rule. Therefore that shows my answer is correct.

I have tried and gone further. I got to the final answer of 1/2(f(x^2))^(-1/2) *f'(x^2)*2x

I have tried and gone further. I got to the final answer of 1/2(f(x^2))^(-1/2) *f'(x^2)*2x Is that my final answer now?

Would I be wise and just restarting all over again, or should I just pick up from where I left off.

I started out by rewriting the function as (f(x^2))^(1/2). I then did chain rule to get 1/2(f(x^2))^(-1/2) *(f'(x^2). - I think I need to go further because it is an x^2 in the function, but not sure.