if m2 is negative then they would end up being zero giving me 0 for theta and velocity, which doesn't make sense.
px: 0 = m1(100)cos(40) - m2(100)cos(40) +(3)m3v3cos(theta)
py: 0 = m1(100)sin(40) - m2(100)sin(40) + (3)m3v3sin(theta)
0 + tan(theta) = 0
ok so iif i split it each angle would be 40 degrees in opposite directions giving me
px: 0 = m1(100)cos(40) + m2(100)cos(40) +(3)m3v3cos(theta)
py: 0 = m1(100)sin(40) + m2(100)sin(40) + (3)m3v3sin(theta)
all the m1 and m2 would then cancel when i divide py by px giving me:
.8355+ tan(theta) =...
1. The Problem: A bomb at rest explodes, breaking into three pieces. Two of the pieces hace equal mass and fly off at 80° of each other with a speed of 100m/s. The tird piece has three times the mass of the other pieces. What is the magnitude and the direction of the third piece?
2...