Recent content by StudentofPhysics

1. An archeological specimen containing 8.7 g of carbon has an activity of 1.6 Bq. How old (in years) is the specimen? 2. Decay constant for Carbon= 0.693 / 5730 yr = 1.21 x 10^-4 1.6/8.7= 0.1839 activity per gram of C 0.23 is Activity of C at t=0 3. ln(0.1839/.23) =...

yea that's what happened I guess or I must've entered it wrong in my calculator some how... anyway, much appreciation for the help.

hmm, rerunning it i get the 2.7 x 10^-7 Joules too, not sure how i got the other number the first time... maybe I wrote it down wrong

ok its correct, I'm going back through it all to see what we did differently.

i did the following: 1.810725 u x 1.6605 x 10^-27 Kg = 3.00671 x 10^-27 Kg 3.00671 x 10^-27 Kg x (c^2) = 5.5715 x 10^-12 J 5.5715 x 10^-12 J / 1.6 x 10^-19 J = 34821826.4 eV = 34.82 MeV

the correct answer in u was 1.810725 u for the mass defect

thats what I did... hmmmwould you mind running it quickly and seeing if you get a number other than 34.8 MeV?

As do we in America, I'm in college.

ok I'm getting it equals 34.8 MeV and this isn't right what am I doing wrong here. Again, my book shows how to convert from kg in J then into eV then into MeV.And I had to use u because that was the required unit in the first part of the problem

ok its right thanks no idea why my book left that out..money well spent

ok i'll try that but my book says nothing about including electrons

mass defect takes place in the nucleus though

1. For astatine 21885At (atomic mass = 218.008684 u) obtain each of the following: (a) The mass defect in atomic mass units wrong check mark u (b) the binding energy (in MeV) MeV (c) the binding energy per nucleon (in MeV) MeV 2. Shown in atempt...

ok I found it by going through the wavelength. Is that the fastest way?

1. The atomic number of osmium is Z = 76. According to the Bohr model, what is the energy (in joules) of a K X-ray photon? 2. ? 3. The reason I left relavent eqns blank is because I used the following: En = -(13.6) Z^2/n^2 subtracting one from Z before squaring and converting...